Hah I bet blue added it for the trolls. Of course with the viral number of 21 going around, surely /21 will be tested... By the way is this a joke?
Well, x = 9 + 10 0 = 9 + 10 - x ∫(9 + 10 - x)dx = ∫0dx 9x + 10X - (1/2)x + C = C 9x + 10x - (1/2)x^2 = 0 2(9x + 10x - (1/2)x^2) = 2*0 18x + 20x - x^2 = 0 0 = x^2 - 38x 0 = x(x - 38) x = 0 x = 38 ∴ 9 + 10 = 0 AND 38
9+10 = 21 (We will assume that the confidence level is 95%) 9 sub-data set 1, 10 sub-data set 2. Checking Conditions... Paired data: The data is paired my mathematical integration Independence: We assume the two data are independent, provided that they have been collected Randomization: We hope that the two data are random, and are representative of all number-data Less than 10%: 9 and 10 are less than 10% of all numbers to exist Nearly Normal: (Its hard to illustrate a histogram on here so... we will skip that) The spread of the histogram is unimodal and mostly symmetric Since all conditions are satisfied, we can use a Students' t-model with 1 degree of freedom, to perform a t-interval. X-Bar = 9.5 Sx = 3.022 Df = 1 Now we can perform our interval equation, with a formula of D-bar plus/minus t*-subscript-df x Sx/sqrN 9.5 +/- 9.16 x 3.022/sqr1 9.5 +/- 9.16 x 3.022 9.5 +/- 27.52 (-17.65 , 36.652) With this, we are 95% confident, that all values that result from the equation "9+10" will equal a value between -17.65 and 36.652
